Integrand size = 13, antiderivative size = 57 \[ \int \frac {1}{x^2 (a+b x)^{3/2}} \, dx=-\frac {3 b}{a^2 \sqrt {a+b x}}-\frac {1}{a x \sqrt {a+b x}}+\frac {3 b \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{5/2}} \]
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Time = 0.01 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {44, 53, 65, 214} \[ \int \frac {1}{x^2 (a+b x)^{3/2}} \, dx=\frac {3 b \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{5/2}}-\frac {3 b}{a^2 \sqrt {a+b x}}-\frac {1}{a x \sqrt {a+b x}} \]
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Rule 44
Rule 53
Rule 65
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {1}{a x \sqrt {a+b x}}-\frac {(3 b) \int \frac {1}{x (a+b x)^{3/2}} \, dx}{2 a} \\ & = -\frac {3 b}{a^2 \sqrt {a+b x}}-\frac {1}{a x \sqrt {a+b x}}-\frac {(3 b) \int \frac {1}{x \sqrt {a+b x}} \, dx}{2 a^2} \\ & = -\frac {3 b}{a^2 \sqrt {a+b x}}-\frac {1}{a x \sqrt {a+b x}}-\frac {3 \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )}{a^2} \\ & = -\frac {3 b}{a^2 \sqrt {a+b x}}-\frac {1}{a x \sqrt {a+b x}}+\frac {3 b \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{5/2}} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.86 \[ \int \frac {1}{x^2 (a+b x)^{3/2}} \, dx=\frac {-a-3 b x}{a^2 x \sqrt {a+b x}}+\frac {3 b \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{5/2}} \]
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Time = 0.10 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.88
method | result | size |
risch | \(-\frac {\sqrt {b x +a}}{a^{2} x}-\frac {b \left (-\frac {6 \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{\sqrt {a}}+\frac {4}{\sqrt {b x +a}}\right )}{2 a^{2}}\) | \(50\) |
pseudoelliptic | \(\frac {3 \sqrt {b x +a}\, \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right ) b x -3 \sqrt {a}\, b x -a^{\frac {3}{2}}}{x \,a^{\frac {5}{2}} \sqrt {b x +a}}\) | \(51\) |
derivativedivides | \(2 b \left (-\frac {1}{a^{2} \sqrt {b x +a}}+\frac {-\frac {\sqrt {b x +a}}{2 b x}+\frac {3 \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{2 \sqrt {a}}}{a^{2}}\right )\) | \(54\) |
default | \(2 b \left (-\frac {1}{a^{2} \sqrt {b x +a}}+\frac {-\frac {\sqrt {b x +a}}{2 b x}+\frac {3 \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{2 \sqrt {a}}}{a^{2}}\right )\) | \(54\) |
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Time = 0.23 (sec) , antiderivative size = 151, normalized size of antiderivative = 2.65 \[ \int \frac {1}{x^2 (a+b x)^{3/2}} \, dx=\left [\frac {3 \, {\left (b^{2} x^{2} + a b x\right )} \sqrt {a} \log \left (\frac {b x + 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) - 2 \, {\left (3 \, a b x + a^{2}\right )} \sqrt {b x + a}}{2 \, {\left (a^{3} b x^{2} + a^{4} x\right )}}, -\frac {3 \, {\left (b^{2} x^{2} + a b x\right )} \sqrt {-a} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (3 \, a b x + a^{2}\right )} \sqrt {b x + a}}{a^{3} b x^{2} + a^{4} x}\right ] \]
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Time = 3.14 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.28 \[ \int \frac {1}{x^2 (a+b x)^{3/2}} \, dx=- \frac {1}{a \sqrt {b} x^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {3 \sqrt {b}}{a^{2} \sqrt {x} \sqrt {\frac {a}{b x} + 1}} + \frac {3 b \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{a^{\frac {5}{2}}} \]
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Time = 0.29 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.33 \[ \int \frac {1}{x^2 (a+b x)^{3/2}} \, dx=-\frac {3 \, {\left (b x + a\right )} b - 2 \, a b}{{\left (b x + a\right )}^{\frac {3}{2}} a^{2} - \sqrt {b x + a} a^{3}} - \frac {3 \, b \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{2 \, a^{\frac {5}{2}}} \]
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Time = 0.31 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.12 \[ \int \frac {1}{x^2 (a+b x)^{3/2}} \, dx=-\frac {3 \, b \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a} a^{2}} - \frac {3 \, {\left (b x + a\right )} b - 2 \, a b}{{\left ({\left (b x + a\right )}^{\frac {3}{2}} - \sqrt {b x + a} a\right )} a^{2}} \]
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Time = 0.14 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.05 \[ \int \frac {1}{x^2 (a+b x)^{3/2}} \, dx=\frac {3\,b\,\mathrm {atanh}\left (\frac {\sqrt {a+b\,x}}{\sqrt {a}}\right )}{a^{5/2}}-\frac {\frac {2\,b}{a}-\frac {3\,b\,\left (a+b\,x\right )}{a^2}}{a\,\sqrt {a+b\,x}-{\left (a+b\,x\right )}^{3/2}} \]
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